Determine the mass of 0.5m^3 of aluminum with relative density of 2.70.
0.5 m^3 * 2.70 * 10^3 kg/m^3
= 1.35 *10^3 kg
= 1350 kg
To determine the mass of a given volume of aluminum with a relative density of 2.70, you can follow these steps:
1. Identify the formula for relative density: Relative Density = Density of Substance / Density of Reference Substance
2. Since the question provides the relative density of aluminum, it is given as 2.70. This means that the density of aluminum is 2.70 times denser than the density of the reference substance, which is usually water.
3. Since the density of water is approximately 1000 kg/m^3, we can determine the density of aluminum by multiplying the relative density by the density of water:
Density of Aluminum = Relative Density * Density of Water
= 2.70 * 1000 kg/m^3
= 2700 kg/m^3
4. Now that we have the density of aluminum, we can calculate the mass using the formula:
Mass = Volume x Density
Given:
Volume = 0.5 m^3
Density = 2700 kg/m^3
Mass = 0.5 m^3 * 2700 kg/m^3
= 1350 kg
So, the mass of 0.5 m^3 of aluminum with a relative density of 2.70 is 1350 kg.