An elevator descends at a rate of 4.5 feet per second. If the elevator begins its descent from a height of 360 feet, at what height will it be after 17 seconds?

hf=hi+vi*t

hf=360-4.5*17

isn't that on a test?

To find the height of the elevator after 17 seconds, we need to calculate the distance it will travel during that time period. We can use the formula:

Distance = Rate x Time

Given that the elevator descends at a rate of 4.5 feet per second, and the time is 17 seconds, we can substitute these values into the formula:

Distance = 4.5 feet/second x 17 seconds
Distance = 76.5 feet

Therefore, after 17 seconds, the elevator will be 76.5 feet lower than its initial height of 360 feet.

To find the final height, we subtract the distance it traveled from the initial height:

Final height = Initial height - Distance traveled
Final height = 360 feet - 76.5 feet
Final height = 283.5 feet

Therefore, after 17 seconds, the elevator will be at a height of 283.5 feet.