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The quadratic function f(x) has roots at x=4 and x=-2 and has value of 2 at x=0. Does f(x) have a minimum or maximum?

Find the value of the /minimum/maximum value of f(x).

asked by Jake
  1. f(x)=a(x-4)(x+2)
    2=a(-4)(2)
    a=-1/4

    f(x)=-1/4 (x-4)(x+2)
    f'=-1/4(x-4)-1/4(x+2)=0
    -x+4-x-2=0
    x=1 max or min
    f"=-2/4 so it is curving down, it is a max at x=1

    posted by bobpursley

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