what is the distance that a satellite must be from Earths surface if it's period of rotation is 1 day?
I really not sure where to even start..
Easy.
Keplers law: r^3=k*T^2
look up for the moon, the radius of its orbit, and period. I get 238,900 miles, and 27 days.
Now you know the period you want, 1 day, so a ratio is
(r/238900)^3= (1/27)^2
solve for r. I get
r=238900(1/27)^2/3 or
r=238900/9= 26500 miles
Look up the numbers, you can get it bit more accurate.