The initial velocity, the final velocity, and the time are given. Using one of the equations of kinematics, you can calculate the displacement directly.
An airplane starts from rest and reaches a takeoff velocity of 60.0 m/s due north in 4.0 s. How far has it traveled before takeoff?
A. 60 m, due north
B. 30 m, due north
C. 240 m, due north
D. 360 m, due north
E. 120 m, due north
The answer is E
Using the equation d= v1*t+1/2at^2
V2 = V1 + a*t.
60 = 0 + a*4, a = 15 m/s^2.
d = V1*t + 0.5a*t^2.
V1 = 0, t = 4 s., a = 15 m/s^2, d = ?.
To calculate the displacement of the airplane before takeoff, we need to use one of the equations of kinematics. In this case, we can use the equation:
displacement = (final velocity - initial velocity) * time
Given:
Initial velocity (u) = 0 m/s (as the airplane starts from rest)
Final velocity (v) = 60.0 m/s due north
Time (t) = 4.0 s
Using the equation, we can substitute the values:
displacement = (60.0 m/s - 0 m/s) * 4.0 s
displacement = 60.0 m/s * 4.0 s
displacement = 240.0 m
Therefore, the airplane has traveled 240 meters before takeoff. The correct answer is option C. 240 m, due north.