Physics

The velocity graph of a particle moving along the x-axis is shown. The particle has zero velocity at t=0.00s and reaches a maximum velocity, vmax, after a total elapsed time, t total. If the initial position of the particle is x0 =6.22m, the maximum velocity of the particle is vmax=47.6m/s, and the total elapsed time is t total=17.6s, what is the particle's position at t=11.7s?

At t=11.7s, what is the particle's velocity?

At t=11.7s, what is the particle's acceleration?



the graph is a linear line increasing from origin

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  1. The area under the graph from t=0 to the time asked for is distance. Since it is a straight line, use your area formulas to figure it out. Distance is the area from y=0 t the graph, from t0 to time t.

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    bobpursley
  2. a=47.6-0/17.6
    a=2.705 seconds

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  3. let me try this again area formula is 1/2 x b x h
    1/2 x 2.705 x 6.22 m/s = 8.4125 m

    is this correct? so after 11.7 seconds the particle position will be 8.4125 m?

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