lim x-->0 [(sin(x)-x)/(x-tan(x))] the answer is 0.5 but I want to know the steps to calculate such a problem
sinx-x = -x^3/3! + x^5/5! - ... x-tanx = -x^3/3 - 2x^5/15 - ... divide both by x^3 and you have -1/3! + x^2/5! - ... -1/3 - 2x^3/15 - ... now divide and let x->0 and (-1/3!)/(-1/3) = 1/2
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