At 275 celcuis K ,an air filled balloon has a volume of 200 liters . If the pressure of the air remains constant, what will its volume be at 300 celsius K ?

To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature, assuming that the pressure remains constant.

Charles's Law can be expressed as:

V1 / T1 = V2 / T2

Where:
V1 = Initial volume (200 liters)
T1 = Initial temperature (275 Celsius K)
V2 = Final volume (unknown)
T2 = Final temperature (300 Celsius K)

We can rearrange the equation to solve for V2:

V2 = (V1 * T2) / T1

Now, let's plug in the given values:

V2 = (200 L * 300 K) / 275 K

Simplifying the equation:

V2 = (60000 L*K) / 275 K
V2 ≈ 218.181818 L

Therefore, the volume of the air-filled balloon at 300 Celsius K will be approximately 218.18 liters.

To solve this problem, we can use Charles's Law, which states that for a fixed amount of gas at a constant pressure, the volume is directly proportional to the temperature in Kelvin.

First, let's convert the temperatures from Celsius to Kelvin. To convert Celsius to Kelvin, we simply add 273 to the Celsius temperature:

Temperature at 275 °C = 275 + 273 = 548 K
Temperature at 300 °C = 300 + 273 = 573 K

Now we can set up the proportion to find the new volume:

(Volume at 275 K) / (Temperature at 275 K) = (Volume at 300 K) / (Temperature at 300 K)

Plugging in the given values:
200 L / 548 K = (Volume at 300 K) / 573 K

Next, we can cross-multiply and solve for the unknown volume:

200 L * 573 K = 548 K * (Volume at 300 K)

After multiplying:
114,600 L * K = 300,144 K * (Volume at 300 K)

Divide both sides by 300,144 K:
114,600 L * K / 300,144 K = Volume at 300 K

Simplifying and dividing:
0.381 L = Volume at 300 K

Therefore, the volume of the air-filled balloon at 300 Celsius K will be approximately 0.381 liters.