8x + 14y = 24
6x + 7y = 10
Solve for x & y
I tried multiple times but I just can't seem to get the right answer.
multiplying 2nd equation by 2
... 12x + 14y = 20
subtracting equations (to eliminate y)
... 4x = -4
solve for x, then substitute back to find y
I still don't understand sir
8x + 14y = 24
6x + 7y = 10
double the 2nd equation and you have
8x + 14y = 24
12x + 14y = 20
Now if you subtract the top from the bottom, the 14y cancels and you have
4x = -4
x = -1
Now use that in either original equation to find y:
8x+14y = 24
8(-1)+14y = 24
-8+14y = 24
14y = 32
y = 16/7
check to be sure that also works in the 2nd equation
To solve this system of equations, you can use either the substitution or the elimination method. Let's solve it using the elimination method:
1. Multiply both sides of equation (1) by 6 and equation (2) by 8 to make the coefficients of x in both equations the same:
Equation (1): 6(8x + 14y) = 6(24) -> 48x + 84y = 144
Equation (2): 8(6x + 7y) = 8(10) -> 48x + 56y = 80
2. Now subtract equation (2) from equation (1) to eliminate the x term:
(48x + 84y) - (48x + 56y) = 144 - 80
Simplifying, we get:
56y - 56y = 64
0 = 64
3. When we reach a contradictory statement like 0 = 64, it means that the system of equations has no solution.
Therefore, in this case, the system of equations is inconsistent, and there is no specific solution for x and y.
If you suspect that the system of equations might be incorrect or you made a mistake in writing them down, it is advisable to double-check the equations and try solving them again.