Two drivers start at the same time to make a 100- km trip. Driver 1 takes 2 hrs to complete the trip. Driver 2 Thames 3 hrs, but stops for an hour at the halfway point. Which driver had a greater average speed for the whole trip? Explain

They both had the same average speed.

Nah, the zero part counts

total distance/total time

To determine which driver had a greater average speed for the whole trip, we need to calculate their respective average speeds.

Average speed is determined by dividing the total distance traveled by the total time taken. So, let's calculate the distance and time taken for each driver.

Driver 1:
Distance traveled = 100 km
Time taken = 2 hours

Driver 2:
Distance traveled = 100 km
Time taken (excluding the 1-hour stop) = 3 hours - 1 hour = 2 hours

To calculate average speed, we divide the distance traveled by the time taken:

Driver 1:
Average speed = 100 km / 2 hours = 50 km/h

Driver 2:
Average speed = 100 km / 2 hours = 50 km/h

Both drivers have an average speed of 50 km/h for their respective segments of the trip. However, we need to consider the entire trip.

Driver 1 completed the trip without any stops in 2 hours, maintaining a constant speed of 50 km/h.

Driver 2 took 3 hours to complete the trip but had a 1-hour stop at the halfway point. Consequently, the overall time taken by Driver 2 was 2 hours (time taken without the stop) + 1 hour (stop time) = 3 hours.

Since both drivers covered the same distance of 100 km, but Driver 2 took 3 hours instead of 2 due to the 1-hour stop, their average speeds for the whole trip would be different.

Driver 1's average speed was 50 km/h for the whole trip, whereas Driver 2's average speed was lower due to the longer total time taken. Therefore, Driver 1 had a greater average speed for the entire trip.