from the balanced equation 4NH3 +7O2 - 4NO2 + 6H2O
How many molecules of water are produced when 2.25 moles of ammonia are completely reacted?
The equation tells us that 4 mol NH3 will produce 6 mols water. That means 2 mols NH3 will produce 3 mols water. How did we do that?
2 mols NH3 x (6 mols H2O/4 mols NH3) = 3 mols H2O. Right? So that factor is what you use.
2.25 mols NH3 x (6 mols H2O/4 mols NH3) = ?? mols H2O.
We know there are 6.02 x 10^23 molecules in one mol. So how many molecules will be in ?? mol H2O.
2.25 mols NH3 x (6 mols H2O/4 mols NH3) = ?? mols H2O
3.4mols
3.4 x 6.02 x 10^23=2.05?
2.25 mols NH3 x (6 mols H2O/4 mols NH3) = ?? mols H2O
3.4mols My calculator gives 3.375 mols. You are allowed 3 places (since there are 3 in the original 2.25 number; therefore, rounding to 3.4 is too harsh. It should be rounded to 3.38 mols.
3.4 x 6.02 x 10^23=2.05?
What did you do with the 10^23?
3.38 x 6.02 x 10^23 = 2.03 x 10^24. Do that on your calculator. Check my arithmethic. I have trouble seeing the calculator buttons.
I got 2.03 x 10^25
No, 2.03 x 10^24 is correct. You may have punched in the wrong exponent.
Well, it seems like you're in deep water with those calculations! But don't worry, I won't make any waves. So, let's dive right in!
From the balanced equation, we know that 4 moles of NH3 produce 6 moles of H2O. That means 2 moles of NH3 will produce 3 moles of H2O. So, multiplying 2.25 moles of NH3 by the conversion factor (6 moles H2O/4 moles NH3) gives us the number of moles of H2O:
2.25 moles NH3 x (6 moles H2O/4 moles NH3) = 3.375 moles H2O.
Now, to determine the number of molecules of H2O, we use Avogadro's number (6.02 x 10^23 molecules per mole):
3.375 moles H2O x (6.02 x 10^23 molecules/1 mole) = 2.0325 x 10^24 molecules of H2O.
So, it looks like we made quite a splash! The correct number of molecules of water produced is approximately 2.03 x 10^24. Just remember, when it comes to calculations, water you waiting for? Dive right in and double-check those numbers!
You are correct, my previous response was incorrect. I apologize for the confusion. The correct calculation is:
2.25 moles NH3 x (6 moles H2O/4 moles NH3) = 3.375 moles H2O
To calculate the number of molecules of water, we use Avogadro's number (6.02 x 10^23) which represents the number of molecules in one mole.
3.375 moles H2O x 6.02 x 10^23 molecules/mole = 2.03 x 10^24 molecules of H2O
To find out how many molecules of water are produced when 2.25 moles of ammonia (NH3) are completely reacted, we can use the balanced equation:
4NH3 + 7O2 → 4NO2 + 6H2O
From the equation, we can see that 4 moles of NH3 produce 6 moles of water. Therefore, in the case of 2 moles of NH3, we can calculate the number of moles of water using the ratio:
2 moles NH3 x (6 moles H2O / 4 moles NH3) = 3 moles H2O
So, 2 moles of NH3 will produce 3 moles of water. To find out how many moles of water are produced from 2.25 moles of NH3, we can use the same ratio:
2.25 moles NH3 x (6 moles H2O / 4 moles NH3) = 3.375 moles H2O
Now, to calculate the number of water molecules, we need to convert the moles of water to the number of molecules. We know that there are 6.02 x 10^23 molecules in one mole. So, we can multiply the number of moles of water by Avogadro's number:
3.375 moles H2O x (6.02 x 10^23 molecules / 1 mole) = 2.03 x 10^24 molecules H2O
Thus, the number of water molecules produced when 2.25 moles of ammonia are completely reacted is 2.03 x 10^24.