Problem #1

what values for x must be excluded in the following fraction?

(x+5)/(-1)

my answer i think its none

Problem #2

what value for x must be excluded in the following fraction?

(x-3)/(4x-5)(x+1)

this one i do not know

x can not equal 5/4 or -1. Each of these would make the denominator zero which is against all laws of mankind.

single

To find the values that must be excluded in a fraction, you need to identify any values of x that would result in a denominator of zero. Dividing by zero is undefined, so those values of x should be excluded.

In Problem #1, the fraction is (x+5)/(-1). Since the denominator is -1, there is no value of x that would make the denominator zero. Therefore, no values of x need to be excluded. Your answer that none should be excluded is correct.

In Problem #2, the fraction is (x-3)/(4x-5)(x+1). To find the values that must be excluded, we need to set the denominator equal to zero and solve for x.

(4x-5)(x+1) = 0

Setting each factor equal to zero, we get:

4x-5 = 0 -> 4x = 5 -> x = 5/4

x+1 = 0 -> x = -1

So, the values x = 5/4 and x = -1 would make the denominator zero. Therefore, these values must be excluded from the domain of the fraction.

To summarize:
- In Problem #1, no values of x need to be excluded.
- In Problem #2, the values x = 5/4 and x = -1 must be excluded.