Would someone please check these for me?

52. In an experiment, you fill a heavy-walled 5.00-L flask with methane gas, CH4. If the flask contains 7.13 g of methane at 19 degrees C, what is the gas pressure?

2.14 atm

56. A 2.50-L flask was used to collect a 5.65-g sample of propane gas, C3H8. After the sample was collected, the gas pressure was found to be 741 mmHg. What was the temperature of the propane in the flask?

232. K

60. Chloroform, CHCl3, is a volatile liquid solvent. Calculate the density of chloroform vapor at 98 degrees C and 797 mmHg. Give the answer in grams per liter.

4.12 g/L

64. A 2.30 g sample of white solid was vaporized in a 345 mL vessel. If the vapor has a pressure of 985 mmHg at 148 degrees C what is the molecular weight of the solid?

177. g/mol

68.
Mg(s) + 2HCl(aq) -> MgCl2(aq) +H2(g)
Calculate the volume (in liters) of hydrogen produced at 33 degrees C and 665 mmHg from 0.0840 mol Mg and excess HCl.

2.41 L

70.
Mg3N2(s) + 6H2O(l) -> 3Mg(OH)2(s) + 2NH3(g)
What volume of ammonia gas at 24 degrees C and 753 mmHg will be produced from 4.56 g of magnesium nitride?

2.22 L

72.
4NH3(g) + 5O2(g) -> 4NO(g) +6H2O(g)
What volume of oxygen at 35 degrees C and 2.15 atm is needed to produce 50.0 g of nitric oxide?

24.5 L

74. Sodium hydrogen carbonate is also known as baking soda. When this compound is heated, it decomposes to sodium carbonate, carbon dioxide, and water vapor. Write the balanced equation for this reaction. What volume of carbon dioxide gas at 77 degrees C and 756 mmHg will be produced from 26.8 g of sodium hyrodgen carbonate?

2NaHCO3(s) -> Na3Co3(aq) + CO2(g) + H2O(g)

4.62 L

76. Calculate the total pressure of a mixture of .0200 mol of He, and .0100 mol of H2, in a 2.50L flask at 10 degrees C. Assume ideal gas behavior.

Ptotal= .300 atm

78.The atmosphere in a sealed diving bell contained O2 and He. If the has mixture has .200 atm of O2 and a total pressure of 3.00 atm, calcultae the mass of helium in 10.0 L of the gas mixture at 20 degrees C.

4.64 g He

I looked at the first four, they are right. Don't you work with someone on chem homework? Like a study group? That is a very effective way to work chem and physics problems.

The equation on 74 should be Na2CO2. I'm sure that's just a typo.

60. I obtained 4.11.
64. I obtained 177.77 which rounds to 178.
74. I obtained 4.607 which rounds to 4.61.
76. I have 0.2788 which rounds to 0.279 atm.
78. I have 4.6588 which rounds to 4.66 g.

To check whether the given answers are correct, we need to go through the calculation steps for each problem. Let's go over the calculations for each problem:

52. In this problem, we are given the mass of methane (7.13 g), the volume of the flask (5.00 L), and the temperature (19 degrees C). To find the gas pressure, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. First, we need to convert the temperature from Celsius to Kelvin:

T(K) = T(C) + 273.15
T = 19 + 273.15 = 292.15 K

The molar mass of methane (CH4) is 16.04 g/mol. We can calculate the number of moles of methane:

n = mass / molar mass
n = 7.13 g / 16.04 g/mol = 0.445 mol

Now, we can substitute the values into the ideal gas law equation:

P(5.00 L) = (0.445 mol)(0.0821 L atm / mol K)(292.15 K)
P = (0.445 mol)(0.0821 L atm / mol K)(292.15 K) / 5.00 L
P ≈ 2.14 atm

The pressure of the methane gas in the flask is approximately 2.14 atm.

56. In this problem, we are given the volume of the flask (2.50 L), the mass of propane (5.65 g), and the pressure (741 mmHg). We need to find the temperature of the propane gas. We can again use the ideal gas law:

PV = nRT

First, we need to convert the pressure from mmHg to atm:

P(atm) = P(mmHg) / 760
P(atm) = 741 mmHg / 760 = 0.974 atm

The molar mass of propane (C3H8) is 44.10 g/mol. We can calculate the number of moles of propane:

n = mass / molar mass
n = 5.65 g / 44.10 g/mol = 0.128 mol

We can now solve for the temperature by rearranging the ideal gas law equation:

T = (P)(V) / (n)(R)
T = (0.974 atm)(2.50 L) / (0.128 mol)(0.0821 L atm / mol K)
T ≈ 232 K

The temperature of the propane gas in the flask is approximately 232 K.

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