When hydrochloric acid reacts with sodium sulfide, hydrogen sulfide gas and sodium chloride are produced. How many moles of H2S will be generated by 2.56 moles of HCl?
2HCl + Na2S → H2S + 2NaCl
one mol of H2S for every 2 mols of HCl
2.56/2 =1.28
That assumes of course that you put in plenty of Na2S
To determine the number of moles of H2S generated by 2.56 moles of HCl, we need to use the mole ratio from the balanced chemical equation.
From the balanced equation:
2 moles of HCl react to produce 1 mole of H2S.
Therefore, we can set up a proportion:
2 moles HCl / 2.56 moles HCl = 1 mole H2S / x
Cross-multiplying and solving for x, we get:
2.56 moles HCl * 1 mole H2S / 2 moles HCl = x
Simplifying, we find:
x = 1.28 moles H2S
Therefore, 2.56 moles of HCl will generate 1.28 moles of H2S.
To determine how many moles of H2S will be generated by 2.56 moles of HCl, we need to use the balanced equation and the stoichiometry of the reaction.
In the balanced equation, we see that 2 moles of HCl react to produce 1 mole of H2S. Therefore, the stoichiometric ratio is 2 moles of HCl : 1 mole of H2S.
To find the moles of H2S produced, we can use the following proportion:
2 moles of HCl / 1 mole of H2S = 2.56 moles of HCl / x moles of H2S
Cross-multiplying, we get:
2.56 moles of HCl * 1 mole of H2S = 2 moles of HCl * x moles of H2S
Simplifying, we get:
2.56 moles of HCl * 1 mole of H2S = 2 * x moles of H2S
2.56 moles of HCl = 2 * x moles of H2S
Dividing both sides by 2, we have:
x moles of H2S = 2.56 moles of HCl / 2
x moles of H2S = 1.28 moles of HCl
Therefore, 2.56 moles of HCl will produce 1.28 moles of H2S.