A rectangle has a width of 12 cm and diagonal of 20 cm find the lenght
12^2 + L^2 = 20^2
L = 16
It's just a 3-4-5 triangle scaled up by a factor of 4.
I am with my answer
Thanku
You're welcome.
To find the length of the rectangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (diagonal in this case) is equal to the sum of the squares of the other two sides (length and width in this case).
Let's denote the length of the rectangle as l and the width as w. We are given that the width is 12 cm and the diagonal is 20 cm. We can set up the following equation:
l^2 + w^2 = diagonal^2
Substituting the given values:
l^2 + 12^2 = 20^2
Simplifying:
l^2 + 144 = 400
Subtracting 144 from both sides:
l^2 = 400 - 144
l^2 = 256
Taking the square root of both sides:
l = √256
l = 16 cm
Therefore, the length of the rectangle is 16 cm.
12^2 + L^2 = 20^2
144 + L^2 = 400
L^2 = 256
L = 16