A 1400 kg car travels up a 20 degrees incline. The car exerts a constant force of 30,000 N across 100m. The car starts from rest at the bottom of the incline. The car takes 10 minutes to do this. How much work is done by the car?
I do not understand what the 30,000 N force is doing, is that in the direction of movement?
If it is, then work done = 10,000*100 Joules
A 1400 kg car accelerates from rest to 95 km/hr in 7.4 sec. Whatb is the average power delivered by the engine?
To calculate the work done by the car, we first need to determine the displacement of the car along the incline. Given that the car travels up a 20 degrees incline and covers a distance of 100m, we can use trigonometry to find the vertical displacement.
The vertical displacement (d) can be calculated using the formula:
d = distance * sin(angle)
In this case, the angle is 20 degrees and the distance is 100m. So,
d = 100 * sin(20)
Now that we have the vertical displacement, we can calculate the work done using the following formula:
work = force * displacement
In this case, the force exerted by the car is 30,000 N and the displacement is the vertical displacement (d) we calculated earlier.
work = 30,000 * d
Now, let's substitute the value of d and calculate the work done.
work = 30,000 * (100 * sin(20))
By evaluating this expression, we can find the amount of work done by the car.