Suppose one person decides to carry out a random act of kindness for three people on Monday. On Tuesday, that same person is kind to three more people, and the three he/she helped on Monday each help three more individuals. If the same circumstances were to occur on Wednesday, how many random acts of kindness would have been distributed?
I think it's 15. Is that right?
1 to 3
initial person does 3 and the other 3 each help 3
so that should be 12
wed.
the initial person does 3
and the other 9 each do 3
27 +3 = 30
63
30
1×3 = 3
1×3 = 3
3×3 = 9
= 15 but they do it again on Wednesday so 15×2= 30
To find the total number of random acts of kindness that would have been distributed by the end of Wednesday, we need to determine the number of acts on each day and then sum them up.
On Monday, one person decides to carry out a random act of kindness for three people. So, the number of acts on Monday is 3.
On Tuesday, the same person is kind to three more people, and the three individuals helped on Monday each help three more individuals. Therefore, on Tuesday, the number of acts is 3 + (3 * 3) = 12.
On Wednesday, following the same pattern, the three people helped on Tuesday (who each helped three more individuals) will carry out their acts of kindness. So, on Wednesday, the number of acts is 3 * 3 * 3 = 27.
To find the total, we add up the acts from each day: 3 + 12 + 27 = 42.
Therefore, the correct answer is 42, not 15.