An object is projected horizontally on a floor at 100ft/s.
It then decceledates at 10ft/s2.
After 5sec what are
a.the speed of the body
b. The distance it traversed
vf=vi+at
where a=-10ft/s^2
distance: d=vi*t-1/2 * 10*t^2
It then decceledates at 10ft/s2.
After 5sec what are
a.the speed of the body
b. The distance it traversed
where a=-10ft/s^2
distance: d=vi*t-1/2 * 10*t^2