The arch of the bridge below is half an ellipse, a "semi-ellipse". The arch is 148m long and has a height of 48m at the center. The height of the arch is 10m at point p. What is the distance from p to the center?

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  1. Draw a diagram.
    Set the center of the ellipse at (0,0). Then we have semi-axes

    a = 74
    b = 48

    x^2/74^2 + y^2/48^2 = 1

    Now plug in y=10 and find x.

    The distance d is then

    d^2 = x^2 + 10^2

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  2. 65561

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  3. how did you get the a=74???

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