0.5M aluminum sulphate aques solution normality calculation
http://www.lagoonsonline.com/laboratory-articles/normality.htm
To calculate the normality of a solution, you need to know the molarity and the acid-base properties of the solute.
Here, we have a 0.5 M aluminum sulfate aqueous solution.
To find the normality, we need to consider how aluminum sulfate dissociates in water.
Aluminum sulfate (Al2(SO4)3) dissociates into three aluminum ions (Al3+) and three sulfate ions (SO4^2-).
In this case, the normality of the solution would be three times the molarity because each aluminum ion contributes a charge of +3.
Normality = 3 * Molarity
Normality = 3 * 0.5 M
Normality = 1.5 N (N stands for normality)
Therefore, the normality of the 0.5 M aluminum sulfate aqueous solution is 1.5 N.