Calculus

Compute F'(-4) where F(x) = x^3 + X^2 (using the definition of the derivative)

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  1. F'(-4)

    = lim(h->0) [((-4+h)^3 + (-4+h)^2) - ((-4)^3+(-4)^2)]/h

    = lim(h->0) [(h^3-11h^2+40h-48)-(-48)]/h

    = lim(h->0) (h^3-11h^2+40h)/h
    = lim(h->0) (h^2-11h+40)
    = 40

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    posted by Steve

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