Using the equation 2H2 + O2 ==> 2H2O, determine how many grams of water is produced when 29 moles of oxygen is consumed
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see your other post...
To determine the number of grams of water produced, we need to use the stoichiometry of the balanced chemical equation.
The balanced chemical equation is: 2H2 + O2 → 2H2O
From the equation, we can see that for every 1 mole of O2 consumed, 2 moles of H2O are produced.
First, we need to convert the moles of O2 to moles of H2O:
29 moles of O2 * (2 moles of H2O / 1 mole of O2) = 58 moles of H2O
Now, we can calculate the grams of water produced using the molar mass of water. The molar mass of water (H2O) is approximately 18.0153 grams/mol:
58 moles of H2O * 18.0153 grams/mol = 1044.89 grams of H2O
Therefore, when 29 moles of oxygen is consumed, approximately 1044.89 grams of water are produced.