An artist draws a picture of a house with a rose bush in front.In his picture the rose bush is 1.5cm high and the house is 7.5cm high.In reality the rose bush is .75 meters high.How tall is the house(in meters)? HINT:set up proportion to solve.
Convert all values to meters, then set up proportion.
X/.075 = .75/.015 = 50
You can complete the calculation.
I hope this helps. Thanks for asking.
To find the height of the house in meters, we can set up a proportion using the given measurements.
Let's assign variables for the height of the rose bush and the height of the house.
Let H represent the height of the house in meters and R represent the height of the rose bush in meters.
From the problem, we know that in the picture the rose bush is 1.5cm high and in reality, it is 0.75 meters high. Similarly, in the picture, the house is 7.5cm high, and we don't know its actual height in meters.
To set up a proportion, we can write:
(Rose bush height in picture)/(House height in picture) = (Rose bush height in reality)/(House height in reality)
Substituting the given values in centimeters:
(1.5 cm)/(7.5 cm) = (0.75 m)/(H)
Now we can solve for H by cross-multiplying and then dividing:
(1.5 cm * H) = (7.5 cm * 0.75 m)
1.5H cm = 5.625 cm*m
To convert cm to meters, divide both sides by 100:
(1.5H cm) / 100 = (5.625 cm*m) / 100
0.015H m = 0.05625 m
Finally, solve for H by dividing both sides by 0.015:
H = 0.05625 m / 0.015
H = 3.75 meters
Therefore, the height of the house in reality is 3.75 meters.