a body at rest is given an innital uniform acceleration of 8.0m/s-2 for 30s,acceleration reduce to 5.0m/s-2 for d next twenty sec.body mentains speed ten for 60s after brought to rest in 20s draw in graph 1.using d graph to calculate 2.maximum speed attain in motion 3.total ...

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However, we cannot graph on these posts.

i need the answer pls

To answer your questions, let's first break down the information provided and understand the given scenario.

1. The body starts from rest and is given an initial uniform acceleration of 8.0 m/s^2 for 30 seconds.
2. After these 30 seconds, the acceleration reduces to 5.0 m/s^2 for the next 20 seconds.
3. The body then maintains a constant speed for 60 seconds.
4. Finally, the body is brought to rest in 20 seconds.

Now, let's tackle your questions one by one:

1. To draw the graph:
- On the x-axis, plot time (t in seconds).
- On the y-axis, plot velocity (v in m/s).

1. From t = 0 to t = 30, the body undergoes uniform acceleration of 8.0 m/s^2.
- The velocity-time graph for this period will be a straight line with a constant positive slope of 8.0 m/s^2.
2. From t = 30 to t = 50, the acceleration reduces to 5.0 m/s^2.
- The velocity-time graph will have a smaller positive slope of 5.0 m/s^2 during this period.
3. From t = 50 to t = 110, the body maintains a constant speed.
- The velocity-time graph will show a straight line parallel to the time axis, indicating constant velocity.
4. Finally, from t = 110 to t = 130, the body is decelerating, brought to rest.
- The velocity-time graph will show a straight line with a constant negative slope.

2. To calculate the maximum speed attained in motion, we need to find the highest point on the velocity-time graph.
- The highest point on the graph represents the maximum speed attained.
- Locate the point on the graph with the highest value on the y-axis, corresponding to the maximum speed.
- Read the corresponding time (x-axis value) at this point.
- This will give you the time at which the maximum speed occurs during the motion.
- Use the equation v = u + at, where v is the final velocity, u is the initial velocity (0 m/s), a is the acceleration, and t is the time.
- Plug in the values of the acceleration and the time at which the maximum speed occurs to calculate the maximum speed.

3. To calculate the total distance covered by the body:
- Divide the entire motion into smaller segments based on the changes in acceleration.
- Calculate the distance covered in each segment separately and then add them all up.
- For the first segment, where the acceleration is 8.0 m/s^2 for 30 seconds, you can use the equation s = ut + (1/2)at^2.
Here, u is the initial velocity (0 m/s), t is the time (30 seconds), and a is the acceleration (8.0 m/s^2).
Plug in these values to calculate the distance covered in this segment.
- Repeat this process for the other segments of the motion, where the acceleration changes.
- Finally, add up the distances covered in each segment to get the total distance covered by the body.

Remember to consistently use the appropriate units (m/s for velocity, m/s^2 for acceleration, and seconds for time) while performing the calculations.

I hope this breakdown and explanation help you understand how to approach these questions.