Length of rectangle is 8 metres less than twice its breadth. If the perimeter of the rectangle is 56 metres.Find its length and breadth

2(b + 2b-8) = 56

Your answer is wrong

2(b+2b-8)=56

To find the length and breadth of the rectangle, we can set up an equation based on the given information.

Let's assume the breadth of the rectangle is 'b' meters.

According to the problem, the length of the rectangle is 8 meters less than twice its breadth, which can be expressed as:

Length = 2b - 8

The perimeter of a rectangle is calculated by adding the lengths of all four sides. In this case, we have two lengths and two breadths.

Perimeter = 2 × (Length + Breadth)

Given the perimeter is 56 meters, we can substitute the length and breadth values into the above equation:

56 = 2 × (2b - 8 + b)

Simplifying,

56 = 2 × (3b - 8)

Dividing both sides by 2,

28 = 3b - 8

Moving -8 to the other side,

3b = 36

Dividing both sides by 3,

b = 12

Now we have the breadth of the rectangle, which is 12 meters. Substituting this value back into the equation for length:

Length = 2b - 8
Length = 2(12) - 8
Length = 16

Therefore, the length of the rectangle is 16 meters and the breadth is 12 meters.