What is the m/m% of NaOH in a solution prepared with 40.0 g NaOH and 400.0 g of water
To find the m/m% (mass/mass percentage) of NaOH in a solution, you need to divide the mass of NaOH by the total mass of the solution, and then multiply the result by 100.
The total mass of the solution is obtained by adding the mass of NaOH and the mass of water. In this case, the mass of NaOH is given as 40.0 g, and the mass of water is given as 400.0 g. So the total mass of the solution is 40.0 g + 400.0 g = 440.0 g.
Now, let's calculate the m/m% of NaOH:
m/m% = (mass of NaOH / total mass of solution) x 100
Substituting the given values:
m/m% = (40.0 g / 440.0 g) x 100
Simplifying:
m/m% = (0.0909) x 100
m/m% = 9.09%
Therefore, the mass/mass percentage of NaOH in the solution is 9.09%.