Instead of oxalate anion, if we use ethylenediamine as the bidentate ligand, what would be the product? What are the donor atoms in en?

Very reactive

Ethylene diamine has two ligand and more reactive

To determine the product when using ethylenediamine (en) as a bidentate ligand instead of oxalate anion, we need to understand the coordination chemistry involved.

Ethylenediamine (en) is a bidentate ligand, meaning it has two donor atoms that can bond with a metal ion. In the case of ethylenediamine, the two nitrogen atoms (N) act as the donor atoms.

When en coordinates with a metal ion, it forms a coordination complex. The metal ion binds to the two nitrogen atoms of en, resulting in a chelate complex. The metal ion forms bonds with both donor atoms, creating a stable coordination compound.

The product formed by the coordination of ethylenediamine with a metal ion depends on the metal ion and its oxidation state. Different metal ions can have specific preferences for ligands and can result in different products when they react with ethylenediamine.

To determine the specific product, you need to specify the metal ion that is reacting with ethylenediamine. Based on the metal ion and its oxidation state, you can find the corresponding coordination complex by referring to the literature or using computational methods.

In summary, when using ethylenediamine (en) as a bidentate ligand, the donor atoms are the two nitrogen atoms (N). The specific product formed depends on the metal ion and its oxidation state that is reacting with ethylenediamine.