Use long division to determine if the divisor is a factor of the dividend.
(-x^2-94x+600)/(x+100)
http://www.purplemath.com/modules/polydiv2.htm
I know how to do long division it's just this problem I'm stuck on.
(-x^2-94x+600)/(x+100)
= -(x^2 + 94x - 600)/(x+100)
= -(x+100)(x - 6)/(x+100)
yup, the divisor is a factor of the dividend.
You claim that you know how to do long division.
Then your result should have yielded the same conclusion. Mine did.
To determine if the divisor, (x+100), is a factor of the dividend, (-x^2-94x+600), we can use long division. Here's how:
Step 1: Divide the first term of the dividend by the first term of the divisor. In this case, (-x^2) divided by (x) gives us -x.
```
-x
-------------
x + 100 | -x^2 - 94x + 600
```
Step 2: Multiply the divisor by the quotient obtained in Step 1 and subtract it from the dividend.
```
-x
-------------
x + 100 | -x^2 - 94x + 600
x^2 + 100x
-------------
6x + 600
```
Step 3: Repeat the process by bringing down the next term of the dividend (in this case, +600), and divide this new dividend (6x + 600) by the divisor (x + 100).
```
-x + 6
-------------
x + 100 | -x^2 - 94x + 600
x^2 + 100x
-------------
6x + 600
- 6x - 600
-------------
0
```
Step 4: We have reached a remainder of 0, which means that the divisor (x + 100) is indeed a factor of the dividend (-x^2 - 94x + 600).
So, (-x^2-94x+600) divided by (x+100) gives us (-x + 6) with a remainder of 0. Therefore, the divisor is a factor of the dividend.