At some distance from a point charge, the electric potential is 566.0 V and the magni- tude of the electric field is 246.0 N/C.
Find the distance from the charge. The value of the Coulomb constant is 8.98755 × 109 N · m2/C2 and the acceleration due to gravity is 9.81 m/s2 .
Answer in units of m.
To find the distance from the point charge, we can use the equation relating electric potential and electric field strength. The equation is:
V = E * d
where V is the electric potential, E is the electric field strength, and d is the distance from the charge.
Given:
V = 566.0 V
E = 246.0 N/C
Plugging these values into the equation, we can solve for d:
566.0 V = 246.0 N/C * d
To isolate d, divide both sides of the equation by 246.0 N/C:
566.0 V / 246.0 N/C = d
Simplifying, we get:
d = 2.2992 m
Therefore, the distance from the charge is approximately 2.2992 meters.