Sarin is a nerve gas with a chemical formula of C4H10FO2P. What is the mass of one molecule of sarin?

To calculate the mass of one molecule of sarin (C4H10FO2P), we need to sum up the atomic masses of all the atoms present in the formula.

The atomic masses of the elements involved are as follows:
Carbon (C) = 12.01 g/mol
Hydrogen (H) = 1.01 g/mol
Fluorine (F) = 18.99 g/mol
Oxygen (O) = 16.00 g/mol
Phosphorus (P) = 30.97 g/mol

Now, let's break down the chemical formula of sarin (C4H10FO2P) and calculate the mass of one molecule:

4 x Carbon (C) = 4 x 12.01 g/mol = 48.04 g/mol
10 x Hydrogen (H) = 10 x 1.01 g/mol = 10.10 g/mol
1 x Fluorine (F) = 1 x 18.99 g/mol = 18.99 g/mol
2 x Oxygen (O) = 2 x 16.00 g/mol = 32.00 g/mol
1 x Phosphorus (P) = 1 x 30.97 g/mol = 30.97 g/mol

Now, add up the masses of all the atoms:
48.04 g/mol + 10.10 g/mol + 18.99 g/mol + 32.00 g/mol + 30.97 g/mol = 140.10 g/mol

Therefore, the mass of one molecule of sarin (C4H10FO2P) is approximately 140.10 g/mol.