A gas mixture consists of equal masses of methane (molecular weight 16.0) and argon (atomic weight 40.0). If the partial pressure of argon is 200. torr, what is the pressure of methane, in torr?

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  1. P V = n R T

    n is number of mols

    say we have 1 mol (n=1) of argon, 40 grams
    then we have 40 grams of Methane
    which is 40/16 or 2.5 mols (n=2.5)
    they both have the same V and T

    P/n = RT/V = same for each
    200/1 = Pmeth/2.5
    Pmeth = 2.5*200 = 500 torr

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