Iron (III) Oxide reacts with Aluminum to form Aluminum Oxide and Iron. If I have 255 g of Aluminum and unlimited Iron (III) oxide, how many grams of Iron will form?

I am really not sure how to work with this. What does it mean when it says that the iron is unlimited, how would you calculate that in? I am unsure how to convert to moles and calculate grams on this one.

asked by Erin
  1. Fe2O3 + Al ---> Al2O3 + Fe

    same number of mols of Fe as of Al

    Al = 30 g/mol
    so 225/30 mols of Al

    so 225/30 mols of Fe
    (225/30) mol mass of Fe

    (225/30)56 = 420 grams of iron

    posted by Damon

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