Iron (III) Oxide reacts with Aluminum to form Aluminum Oxide and Iron. If I have 255 g of Aluminum and unlimited Iron (III) oxide, how many grams of Iron will form?
I am really not sure how to work with this. What does it mean when it says that the iron is unlimited, how would you calculate that in? I am unsure how to convert to moles and calculate grams on this one.
Fe2O3 + Al ---> Al2O3 + Fe
same number of mols of Fe as of Al
Al = 30 g/mol
so 225/30 mols of Al
so 225/30 mols of Fe
(225/30) mol mass of Fe
(225/30)56 = 420 grams of ironposted by Damon