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express log9 in terms of log3 x and log3 y and solve for x and y simultaneously

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  1. let log3 x = a and log3 y = b
    then:
    3^a = x and 3^b = y
    3^a (3^b) = xy
    3^(a+b) = xy
    (9^(1/2))(a+b) = xy
    9^(a+b)/2 = xy

    log9>/sub> xy = (a+b)/2

    can you do anything with that?

    btw, what does log 9 mean?
    is 9 the base, as I assumed ? But then the logarithm had no argument.
    Is there a typo?

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