If the roots of a quadratic equation are -2 and 3, the equation can be written as

a.(x+2)(x+3)=0
b.(x-2)(x+3)=0
c.(x+2)(x-3)=0
d.(x-2)(x-3)=0

thank you!

Its c

Well, the roots of the quadratic equation are -2 and 3. Let's use our bot math skills to find the equation with these roots.

If the roots are -2 and 3, and we want to have an equation equal to zero, we can set up two factors: (x - (-2)) and (x - 3).

Simplifying these factors, we get (x + 2) and (x - 3).

Multiplying these two factors together, we get (x + 2)(x - 3) = 0.

Therefore, the correct answer is option c.(x + 2)(x - 3) = 0.

Keep in mind that a clown might have a different answer because they like to play tricks on unsuspecting mathematicians!

To find the correct equation, we need to use the information provided regarding the roots of the quadratic equation.

The roots of a quadratic equation are the values of 'x' that make the equation equal to zero. In this case, the roots are -2 and 3. If a quadratic equation has roots at -2 and 3, it means that when we substitute -2 and 3 into the equation, it should equal zero.

Let's go through the answer choices and see which equation satisfies this condition:

a. (x+2)(x+3) = 0:
To check if this is the correct equation, we can use the zero product property. According to the zero product property, if the product of two factors is equal to zero, then at least one of the factors must be zero. Therefore, for this equation to be true, either (x+2) must be equal to zero, or (x+3) must be equal to zero. Solving these equations individually, we get x = -2 or x = -3. However, neither of these roots matches the given roots (-2 and 3), so option a is incorrect.

b. (x-2)(x+3) = 0:
Using the same logic, for this equation to be true, either (x-2) must be zero or (x+3) must be zero. Solving these equations individually, we get x = 2 or x = -3. One of these roots, x = -3, matches the given root. Therefore, option b is the correct equation.

c. (x+2)(x-3) = 0:
Using similar reasoning, we can solve the equations (x+2) = 0 and (x-3) = 0 separately. We find x = -2 and x = 3 as the roots, which are the given roots. Therefore, option c is also a correct equation.

d. (x-2)(x-3) = 0:
Using the zero product property, we can solve the equations (x-2) = 0 and (x-3) = 0 separately. This gives us x = 2 and x = 3 as the roots, which are not the given roots. Therefore, option d is incorrect.

In conclusion, the equation that can be written as (x-2)(x+3) = 0 or (x+2)(x-3) = 0. Both option b and option c are correct equations.

( x - x1 ) ( x - x2 ) =

[ x - ( - 2 ) ] ( x - 3 ) =

( x + 2 ) ( x - 3 ) = 0

Answer c.