You have 10.0 ml of a 5.0% NaCl solution. To this you add 5.00ml of a 2.0% NaCl solution. What is the molarity of NaCl in this final mixture?

Na = .05*10 + .02*5 = .6

percent NaCl = .6/15 *100 = 4% =.04

.04/15ml = 40/15 grams/liter

so what is 40 grams of NaCl in mols?

40g/58.44 g/mol = .684 M

label 5 tubes 1-5. Ad 1.50 ml of diluent to each tube. to the first tube, add 500 ul of 1.00 M glucose and mix. transfer 500 ul from the first tube to the second tube and mix. similarly, continue to transfer 500l from each of the remaining tubes to the tube that follows it until all five tubes have been used. what is the final concentration of glucose in tube 5.

To find the molarity of NaCl in the final mixture, we need to first calculate the total amount of NaCl in the solution.

For the 10.0 ml of a 5.0% NaCl solution, the mass/volume percent (w/v %) concentration means that there is 5.0 grams of NaCl present in 100 ml of the solution.

So, in 10.0 ml, the amount of NaCl can be calculated using the following proportion:

(5.0 grams / 100 ml) = (x grams / 10.0 ml)

Solving for x gives:

x = (5.0 grams / 100 ml) * 10.0 ml = 0.50 grams of NaCl in the 10.0 ml solution

Next, let's calculate the amount of NaCl in the 5.00 ml of a 2.0% NaCl solution.

Similar to the previous calculation, we can find the amount of NaCl using the proportion:

(2.0 grams / 100 ml) = (y grams / 5.00 ml)

Solving for y gives:

y = (2.0 grams / 100 ml) * 5.00 ml = 0.10 grams of NaCl in the 5.00 ml solution

Now, we can find the total mass of NaCl in the final mixture by adding the masses from the two solutions:

Total mass of NaCl = 0.50 grams + 0.10 grams = 0.60 grams

Finally, we need to calculate the volume of the final solution, which is the sum of the volumes of the two solutions:

Total volume = 10.0 ml + 5.00 ml = 15.0 ml

Now we can calculate the molarity (M) of NaCl by dividing the moles of NaCl by the volume in liters:

Molarity (M) = moles of NaCl / volume of solution in liters

First, let's convert the mass of NaCl to moles using the molar mass of NaCl, which is 58.44 g/mol:

moles of NaCl = 0.60 grams / 58.44 g/mol = 0.010 mol

Now, we need to convert the total volume to liters:

volume of solution in liters = 15.0 ml / 1000 ml/L = 0.015 L

Finally, we can calculate the molarity by dividing the moles of NaCl by the volume in liters:

Molarity (M) = 0.010 mol / 0.015 L = 0.67 M

Therefore, the molarity of NaCl in the final mixture is 0.67 M.