A outdoor swimming pool is 3.0 m wide and 10.0 m long. If the weekly evaporation is 4.0 cm, how many laters of water must be added to the pool weekly if it does not rain.???
Area = 30m^2=30*10^4 cm^2
30*10^4 * 4 =120*10^4 cm^3/week
there are 1000 cm^3/liter
so
120*10^1 = 1200 liters
if 4cm evaporation occurs again the next week even with 29mm rainfall, how many litres of water should be added to the pool
To find out how many liters of water must be added to the pool weekly, we need to calculate the volume of water lost due to evaporation.
First, let's convert the dimensions of the swimming pool from meters to centimeters:
Width = 3.0 m = 300 cm
Length = 10.0 m = 1000 cm
The evaporation rate is given as 4.0 cm per week.
To calculate the volume of water lost due to evaporation, we multiply the area of the pool by the evaporation rate.
Area of the pool = Length x Width
= 1000 cm x 300 cm
= 300,000 cm²
Volume of water lost due to evaporation = Area x Evaporation rate
= 300,000 cm² x 4.0 cm
= 1,200,000 cm³
Now, we can convert the volume of water lost to liters by dividing by 1000 (since 1000 cm³ = 1 liter).
Volume of water lost in liters = 1,200,000 cm³ / 1000
= 1,200 liters
Therefore, 1,200 liters of water must be added to the pool weekly to compensate for evaporation, assuming no rain.