8ax+4b = 4cx+d
i guess u wanna determine x in terms of a,b,c
8ax+4b=4cx+d
8ax-4cx=d-4b
x(8a-4c)=(d-4b)
x=(d-4b)/(8a-4c)
correct, as long as a does not equal 1/2 c. Division by zero is never allowed.
The given equation is 8ax + 4b = 4cx + d.
To solve this equation, we need to isolate x or find a relationship between the variables.
First, let's group the terms with 'x' on one side of the equation by subtracting 4cx from both sides:
8ax - 4cx + 4b = d
Next, let's factor out 'x' from the terms that contain it:
x(8a - 4c) = d - 4b
To isolate 'x', divide both sides of the equation by (8a - 4c):
x = (d - 4b) / (8a - 4c)
Therefore, the solution to the equation is x = (d - 4b) / (8a - 4c).
You can substitute the values of a, b, c, and d into the equation to find the specific value of x.