If the coefficient of sliding friction for steel on ice is 0.05, what force is required to keep a man weighing 150 lbs moving at constant speed along ice?

150 * .05 pounds

thanks, Jiskha Homework Help

Well, if the coefficient of sliding friction for steel on ice is 0.05, I suppose we could say that the situation is a bit "slippery." Now, let's tackle the problem.

To find the force required to keep the man moving at constant speed along the ice, we need to consider the force of friction. The force of friction can be calculated using the formula: force of friction = coefficient of friction * normal force.

The normal force is the force exerted by the surface perpendicular to the man's weight. Since the man weighs 150 lbs, we can say that the normal force is also 150 lbs (ignoring other forces like buoyancy for now).

So, the force of friction would be: force of friction = 0.05 * 150 lbs.

Calculating that, we get: force of friction = 7.5 lbs.

Therefore, approximately 7.5 lbs of force would be required to keep our slippery man moving at constant speed along the ice. Just be careful not to send him skating off into the sunset!

To determine the force required to keep a man moving at a constant speed along ice, we need to calculate the force of sliding friction.

The force of sliding friction can be calculated using the equation:

F = μ * N

where:
F is the force of sliding friction,
μ is the coefficient of sliding friction, and
N is the normal force.

The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the normal force is equal to the man's weight.

First, let's convert the man's weight from pounds to Newtons, since the SI unit for force is Newtons.

1 pound (lb) is approximately equal to 4.45 Newtons (N).

So, the man's weight is:
150 lb * 4.45 N/lb ≈ 667.5 N

Since the coefficient of sliding friction is given as 0.05, we can substitute the values into the equation to find the force of sliding friction:

F = 0.05 * 667.5 N
F ≈ 33.375 N

Therefore, the force required to keep the man moving at constant speed along ice is approximately 33.375 Newtons.

50 N