When a 37.00 g silver spoon, initially at room temperature, is placed into 250.0mL of 90.00oC tea, it reaches a temperature of 85.00°C. The spoon will have gained ? J of thermal energy.
I got 5237.5 Joules as (mass)x(specific heat capacity)x(Temperature change)=Heat,
which was apparently incorrect.
Please note that we are NOT given the specific heat capacity of silver in this question.
the tea (water) loses the energy gained by the spoon
250.0 * (90.00 - 85.00) * 4.184
4 sig fig ... not 5 as in your answer
To solve this problem, you can use the equation:
Q = mcΔT
Where:
Q = thermal energy gained or lost (in joules)
m = mass (in kilograms)
c = specific heat capacity (in joules per gram per degree Celsius)
ΔT = change in temperature (in degrees Celsius)
Let's convert the given mass from grams to kilograms:
37.00 g = 0.037 kg
And let's calculate the change in temperature:
ΔT = final temperature - initial temperature
ΔT = 85.00°C - room temperature
Since the initial temperature is not given, we can use room temperature, which is approximately 25°C. So the change in temperature is:
ΔT = 85.00°C - 25.00°C
ΔT = 60.00°C
Now we need to find the specific heat capacity of silver. Let's assume it is 0.235 J/g°C.
Using the equation Q = mcΔT, we can calculate the thermal energy gained:
Q = (0.037 kg) x (0.235 J/g°C) x (60.00°C)
Now, we need to convert grams to kilograms and calculate Q:
Q = (0.037 kg) x (0.235 J/g°C) x (60.00°C)
Q = 0.52 Joules
Therefore, the spoon will have gained approximately 0.52 Joules of thermal energy when placed into the tea.
To find the thermal energy gained by the silver spoon, you can use the concept of heat transfer, which is given by the formula:
Q = m * c * ∆T
Where:
Q is the thermal energy gained or lost (in Joules),
m is the mass of the substance (in grams),
c is the specific heat capacity (in J/g°C), and
∆T is the change in temperature (in °C).
In this case, you are looking for the thermal energy gained by the spoon, so the formula becomes:
Q (spoon) = m (spoon) * c (silver) * ∆T
Now, in order to calculate the thermal energy gained by the spoon, we need to use the given temperature data and the specific heat capacity of water. The tea is initially at 90.00°C and the final temperature is 85.00°C, so the change in temperature (∆T) will be:
∆T = T (final) - T (initial)
= 85.00°C - 90.00°C
= -5.00°C
Notice that the temperature change is negative because the spoon loses heat in this case.
Now, we can substitute the values into the formula:
Q (spoon) = m (spoon) * c (silver) * ∆T
Given:
m (spoon) = 37.00 g
∆T = -5.00°C
However, we are missing the specific heat capacity of silver. The specific heat capacity describes how much energy is needed to change the temperature of a certain substance by a certain amount. Unfortunately, you haven't been provided with the specific heat capacity of silver in this question.
To calculate the thermal energy gained by the spoon accurately, you will need to know the specific heat capacity of silver. If this information is not provided, it may be an oversight in the question, or you may need to assume a typical value for the specific heat capacity of silver (0.235 J/g°C).
Alternatively, you can try to find the specific heat capacity of silver by searching for reliable sources such as textbooks, scientific articles, or online databases.