Calculate the amount of fluorescein (MW 332.31) you will need to make 10 mL of 15 mM solution in ethanol (EtOH).
My answer:0.05 g
2.Using Equation C1V1=C2V2 calculate the volume of stock solution (15 mM) you need to make 1 mL of each working solution concentration: 0 mM and 0.25 mM. Remember to convert your volumes to microliter.
My answers:
volume for 0mM --> 0 microliter
volume for 0.25 mM--> 16.67 ~ 17 microliter
3. Calculate the volume of DI H2O needed for each. Remember that this volume will be the total final volume minus the volume of stock solution you calculated.
My answers:
volume of water for the 0 mM --> 10,000 microliter subtract 0 microliter = 10,000 microliter
Your abbreviations are totally confusing.
I read mM as millimolarity
and I have no idea how this translates to micro in your answers.
I need to convert my answer (volume) into microliter.
To calculate the amount of fluorescein you will need to make a 10 mL of 15 mM solution in ethanol (EtOH), follow these steps:
1. Start by calculating the moles of fluorescein required:
Moles = concentration (mM) x volume (L)
Moles = 15 mM x (10 mL / 1000 mL/L)
Moles = 0.15 mmol
2. Convert moles to grams using the molecular weight (MW) of fluorescein:
Mass (g) = Moles x MW
Mass (g) = 0.15 mmol x 332.31 g/mol
Mass (g) = 0.0498 g
3. Round the calculated mass to an appropriate number of significant figures:
Mass (g) = 0.05 g
Therefore, you will need approximately 0.05 g of fluorescein to make a 10 mL 15 mM solution in ethanol (EtOH).
For the second part of your question, you are asked to calculate the volume of stock solution (15 mM) needed to make working solutions with concentrations of 0 mM and 0.25 mM in 1 mL. Using the equation C1V1 = C2V2, where C1 and V1 are the concentration and volume of the initial solution, and C2 and V2 are the concentration and volume of the final desired solution, you can solve for V1.
For 0 mM working solution:
C1 = 15 mM
V1 = ?
C2 = 0 mM
V2 = 1 mL
Using C1V1 = C2V2:
15 mM x V1 = 0 mM x 1 mL
V1 = 0 mM x 1 mL / 15 mM
V1 = 0 mL
Therefore, for the 0 mM working solution, you would need to add 0 microliters of the stock solution to make 1 mL.
For the 0.25 mM working solution:
C1 = 15 mM
V1 = ?
C2 = 0.25 mM
V2 = 1 mL
Using C1V1 = C2V2:
15 mM x V1 = 0.25 mM x 1 mL
V1 = (0.25 mM x 1 mL) / 15 mM
V1 = 0.0167 mL
To convert this volume to microliters:
V1 (in microliters) = 0.0167 mL x 1000 microliters/mL
V1 (in microliters) = 16.67 microliters
Therefore, for the 0.25 mM working solution, you would need to add approximately 17 microliters of the stock solution to make 1 mL.
Finally, for the third part of your question, you need to calculate the volume of DI H2O (water) needed for each working solution. This volume will be the total final volume minus the volume of stock solution you calculated.
For the 0 mM working solution:
Volume of water = Total final volume - Volume of stock solution
Volume of water = 1 mL - 0 mL
Volume of water = 1 mL
Therefore, for the 0 mM working solution, you would need 10,000 microliters (or 10 mL) of DI H2O.
For the 0.25 mM working solution:
Volume of water = Total final volume - Volume of stock solution
Volume of water = 1 mL - 16.67 microliters
Volume of water = 1 mL - 16.67 microliters
Volume of water = 0.9833 mL
To convert this volume to microliters:
Volume of water (in microliters) = 0.9833 mL x 1000 microliters/mL
Volume of water (in microliters) = 983.3 microliters
Therefore, for the 0.25 mM working solution, you would need approximately 983.3 microliters (or 0.9833 mL) of DI H2O.