the function of y= 0.81t^2 relates the time t in seconds, that it takes a problem of length y, in feet, to swing back and forth one time. about how long would it take a 3- ft pendulum to swing back and forth one time? round to the nearest tenth.
Can someone please help me? :(( I badly need it now :(((
what, you can't just plug in the number and find t?
0.81t^2 = 3
t^2 = 3/.81 = 3.7037
t = 1.9245
To find the time it takes for a 3-ft pendulum to swing back and forth one time, you can use the given function: y = 0.81t^2, where y represents the length of the pendulum in feet and t represents the time in seconds.
Given y = 3 ft, we need to solve for t.
Substituting y = 3 into the equation, we have:
3 = 0.81t^2
Divide both sides by 0.81:
3/0.81 = t^2
t^2 ≈ 3.7037
To solve for t, we take the square root of both sides:
t ≈ √3.7037
t ≈ 1.9231
Rounding to the nearest tenth, the time it takes for a 3-ft pendulum to swing back and forth one time is approximately 1.9 seconds.
To determine how long it would take for a 3-ft pendulum to swing back and forth one time, we need to substitute the given value of y into the equation y = 0.81t^2 and solve for t.
Here's how to do it step-by-step:
1. Substitute the value of y (length of the pendulum) into the equation:
y = 0.81t^2
3 = 0.81t^2
2. Divide both sides of the equation by 0.81 to isolate t^2:
3/0.81 = t^2
3. Solve for t^2 by taking the square root of both sides:
√(3/0.81) = t
4. Use a calculator to simplify the square root:
√(3/0.81) ≈ 1.867
5. Round the result to the nearest tenth:
t ≈ 1.9
Therefore, it would take approximately 1.9 seconds for a 3-ft pendulum to swing back and forth one time.