0.001N NaoH calculate the ph
pOH = -log(NaOH)
Then pH + pOH = pKw = 14. You know pKw and pOH, solve for pH.
To calculate the pH of a solution of 0.001 N NaOH (sodium hydroxide), you will need to use the formula for pH, which is defined as the negative logarithm (base 10) of the concentration of H+ ions in the solution. In this case, NaOH is a strong base that fully dissociates in water, so we can assume that all of the NaOH molecules will dissociate into Na+ and OH- ions.
First, let's determine the concentration of OH- ions in the solution. Since NaOH dissociates into one Na+ ion and one OH- ion, the concentration of OH- ions is the same as the concentration of NaOH. In this case, the concentration of NaOH is given as 0.001 N.
Next, we can use the equation for pOH, which is the negative logarithm (base 10) of the concentration of OH- ions:
pOH = -log[OH-]
In this case, pOH = -log(0.001) = 3.
To find the pH of the solution, we can use the relationship between pH and pOH, which is:
pH + pOH = 14
Substituting the given value of pOH:
pH + 3 = 14
Solving for pH:
pH = 14 - 3 = 11
Therefore, the pH of a 0.001 N NaOH solution is 11.