Part (a) of the drawing shows a bucket of water suspended from the pulley of a well; the tension in the rope is 56.0 N. Part (b) shows the same bucket of water being pulled up from the well at a constant velocity. What is the tension in the rope in part (b)?

The same. If there is no acceleration there is no change in force (ignoring friction).

To find the tension in the rope in part (b), we need to understand the concept of equilibrium.

In part (a), when the bucket of water is suspended from the pulley, the system is in equilibrium. This means that the forces acting on the bucket are balanced, with no net force causing any acceleration. Therefore, the tension in the rope is equal to the weight of the bucket.

The weight of an object can be calculated using the formula:

Weight = mass × acceleration due to gravity

In this case, since the bucket is at rest, the acceleration is zero. Therefore, we can simply use the formula:

Weight = mass × gravity

Assuming the acceleration due to gravity is 9.8 m/s², and the weight of the bucket is given as 56.0 N, we can calculate the mass of the bucket as follows:

mass = Weight / gravity
mass = 56.0 N / 9.8 m/s²

After finding the mass of the bucket in part (a), we can use the same mass value to find the tension in the rope in part (b). Since the bucket is being pulled up at a constant velocity, it means there is no acceleration. Therefore, the forces acting on the bucket in part (b) are also in equilibrium. This implies that the tension in the rope will be equal to the weight of the bucket, as in part (a).

By following this process, we can calculate the tension in the rope in both parts (a) and (b).