Calculus

A particle moves along the x-axis with position function s(t) = e^cos(x). How many times in the interval [0, 2π] is the velocity equal to 0?
1< My answer
2
3
More than 3
I don't really get this question will someone please explain it to me?

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  1. v(x) = -sin(x) e^cos(x)

    since e^cos(x) is never zero, how many times in sin(x) = 0 in the interval?

    Your answer is correct on the interval (0,2π), but not on [0,2π]

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  2. what is the difference between the two?

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  3. v(t) = 0 at 0,π,2π

    If you exclude the endpoints of the interval, your answer is correct. But, we are working with the closed interval, including the endpoints. So, there are 3 points where v(t) = 0.

    Better review interval notation.

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