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Calculus

The end behavior of f(x)=(2+x^2)/(x^2-36) most closely matches which of the following:
y=1
y=-1
y=2
y=0
There is no leading coefficient so I am not sure what the answer is.

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  1. CORRECTION: THE SECOND OPTION IS NOT Y=-1 it is Y=-18

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  2. The end behavior of f(x)=(2+x^2)/(x^2-36) most closely matches which of the following:
    y=1
    y=-18
    y=2
    y=0

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  3. as x gets huge, the 2 and the 36 become insignificant:

    y -> x^2/x^2

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  4. so the answer is 2?

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  5. since when is x^2/x^2 = 2?

    10/10 = 1
    z^3/z^3 = 1

    don't forget your Algebra I now that you're taking calculus.

    Using the usual method, divide top and bottom by x^2. That gives you

    (1 + 2/x^2)/(1 - 36/x^2)

    as x^2 gets huge, 1/x^2 -> 0
    and the fraction becomes 1/1

    NOT 2!!

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  6. ok THANK YOU!!!!!!!

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