calculate the specific heat capacity of the materials for which the heat supply, mass, and temperature rises are given below:
i)25200J, 0.3Kg
ii)8000J, 500g, from 20'C to 60'C
iii)9450J, 150g, from 15'C to 45'C
no delta Temp on i
on ii: C=8000/(500*40) in J/gC
To calculate the specific heat capacity (c) of a material, you need to use the formula:
c = Q / (m * ΔT)
Where:
- c is the specific heat capacity (in J/kg·K or J/g·K)
- Q is the heat supplied (in J)
- m is the mass of the material (in kg or g)
- ΔT is the change in temperature (in K or °C)
Let's calculate the specific heat capacity for each case:
i) Q = 25200 J, m = 0.3 kg, ΔT = ? (not given)
We need the change in temperature (ΔT) for this calculation.
ii) Q = 8000 J, m = 500 g, ΔT = (60°C - 20°C) = 40°C
First, convert the mass to kg: m = 500 g = 0.5 kg
Now we can calculate the specific heat capacity:
c = Q / (m * ΔT)
= 8000 J / (0.5 kg * 40 K)
= 400 J/kg·K
iii) Q = 9450 J, m = 150 g, ΔT = (45°C - 15°C) = 30°C
First, convert the mass to kg: m = 150 g = 0.15 kg
Now we can calculate the specific heat capacity:
c = Q / (m * ΔT)
= 9450 J / (0.15 kg * 30 K)
= 630 J/kg·K
So, for the given cases:
i) The specific heat capacity cannot be calculated without the change in temperature.
ii) The specific heat capacity is 400 J/kg·K.
iii) The specific heat capacity is 630 J/kg·K.