if m ac= 50 and mdb= 110 find m<aec
This can't be answered without the diagram that should be with it.
i need help using the foil method when multipling with i and radicals
find the equivalent to sin 150
(1) cos 30 (2) sin 30 (3) sin-30
(4)-sin 30
To find the value of m<aec, we need to analyze the given information and establish the relations between the angles.
From the given information:
m(ac) = 50 (1)
m(db) = 110 (2)
Now, let's consider the triangle ADB and triangle AEC. These triangles are formed by the intersecting line segments of ac and db. We can observe that angle m<aec is an exterior angle formed when ac intersects with db.
According to the properties of parallel lines and transversals, we can establish the following angle relationships:
m<aec = m<adb + m<dbc (3)
In order to find m<aec, we need to determine m<adb and m<dbc.
From equation (1), we have m(ac) = 50, and from equation (2), we have m(db) = 110.
To find m<adb, we can notice that it is the same as m<ac. Therefore, m<adb = m(ac) = 50.
To find m<dbc, we can utilize the rule that states if two lines are parallel, then alternate interior angles are congruent. Given that ac is parallel to db (since they are transversals of a parallel line), we can conclude that m<db = m<acb.
Using this information, we can now find m<db and m<db = 180 - m<adb = 180 - 50 = 130.
Now, substituting the values of m<adb = 50 and m<db = 130 into equation (3), we can find:
m<aec = m<adb + m<dbc
= 50 + 130
= 180
Therefore, m<aec is equal to 180 degrees.