# Calculus

Please.... I need your help! I posted this question yesterday and no one has answered it yet. Can anyone help me please? My question was:

The Taylor series about x=5 for a certain function f converges to f(x) for all x in the interval of convergence. The nth derivative of f at x=5 is given by f^(n) (5)= (-1)^n(n!)/((2^n)(n+2)), and f(5)=1/2.
Write third degree Taylor polynomial for f about x=5. Then find the radius of convergence of the Taylor series for f about x=5.

Do you mean the "nth derivative" or the "nth term in the (first)derivative"? of f(x)? It looks like you have written the coefficient of one term in a Taylor series, without the x^n term coefficient that should accompany it.

x=2

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