CuCO3=CuO +CO2.
Find the mass of 1mole of each substance taking part in the reaction. (Ar:Cu=64,C=12,O=16).
When 31g of CuCO3 is used;
1)how many grams of CO2 is formed.
2) what mass of solid remains after heating.
Where does number 31 comes from?
CuCO3 = 64+12+48 g/mol = 124 g
31/124 = .25 mol
CO2 = 12+32 = 44 g/mol
so 11 g for .25 mol
for CuO, subtract:)
31-11 = 20 grams
check:
CuO = 64+16 = 80 g/mol
.25*80 = 20 grams sure enough
What about answer number 2?
31 is given in the qn
Well, well, well! Looks like we have a chemistry question here. Don't worry, I may not have a degree, but I'll give it a shot!
1) So, let's calculate the mass of 1 mole of CuCO3. CuCO3 has one copper (Cu) atom, one carbon (C) atom, and three oxygen (O) atoms. According to their atomic masses, we have:
Cu: 64 grams/mol
C: 12 grams/mol
O: 16 grams/mol
Adding these up, we get:
1(Cu) + 1(C) + 3(O) = 64 + 12 + 3(16) = 64 + 12 + 48 = 124 grams/mol
Now, to find how many grams of CO2 is formed when 31g of CuCO3 is used, we use the stoichiometry of the balanced chemical equation: CuCO3 = CuO + CO2.
The molar ratio between CuCO3 and CO2 is 1:1, meaning for every 1 mole of CuCO3, we get 1 mole of CO2. Since we know the molar mass of CuCO3 is 124 grams/mol, we divide 31 grams (the given mass of CuCO3) by 124 grams/mol:
31g / 124 grams/mol = 0.25 mol
Since the molar ratio between CuCO3 and CO2 is 1:1, we have the same number of moles of CO2. Therefore, we have 0.25 moles of CO2.
Now, to find the mass of CO2, we multiply the number of moles by the molar mass of CO2 (44 grams/mol):
0.25 mol * 44 grams/mol = 11 grams
So, 31 grams of CuCO3 will give us 11 grams of CO2!
2) Now, to figure out the mass of solid remaining after heating, we need to subtract the mass of CO2 formed from the initial mass of CuCO3.
Given that we formed 11 grams of CO2, we subtract that from the initial 31 grams of CuCO3:
31 grams - 11 grams = 20 grams
After heating, we are left with 20 grams of solid.
So there you have it! 11 grams of CO2 is formed and 20 grams of solid remains after heating 31 grams of CuCO3.
To find the mass of 1 mole of each substance, we can use the atomic masses given in the question.
1) Mass of 1 mole of CuCO3:
CuCO3 molecule consists of one Cu atom (atomic mass = 64 g/mol), one C atom (atomic mass = 12 g/mol), and three O atoms (atomic mass = 16 g/mol each).
So, mass of 1 mole of CuCO3 = (1 × atomic mass of Cu) + (1 × atomic mass of C) + (3 × atomic mass of O)
= (1 × 64 g/mol) + (1 × 12 g/mol) + (3 × 16 g/mol)
= 64 g/mol + 12 g/mol + 48 g/mol
= 124 g/mol
2) Mass of 1 mole of CuO:
CuO molecule consists of one Cu atom (atomic mass = 64 g/mol) and one O atom (atomic mass = 16 g/mol).
So, mass of 1 mole of CuO = (1 × atomic mass of Cu) + (1 × atomic mass of O)
= (1 × 64 g/mol) + (1 × 16 g/mol)
= 64 g/mol + 16 g/mol
= 80 g/mol
3) Mass of 1 mole of CO2:
CO2 molecule consists of one C atom (atomic mass = 12 g/mol) and two O atoms (atomic mass = 16 g/mol each).
So, mass of 1 mole of CO2 = (1 × atomic mass of C) + (2 × atomic mass of O)
= (1 × 12 g/mol) + (2 × 16 g/mol)
= 12 g/mol + 32 g/mol
= 44 g/mol
Now, let's use this information to answer the given questions:
1) To find the mass of CO2 formed, we need to determine the moles of CuCO3 used and then use the mole ratio between CuCO3 and CO2 in the balanced equation.
Molar mass of CuCO3 = 124 g/mol
Moles of CuCO3 used = mass of CuCO3 used / molar mass of CuCO3
= 31 g / 124 g/mol
= 0.25 mol
According to the balanced equation, the mole ratio between CuCO3 and CO2 is 1:1. This means that for every mole of CuCO3, 1 mole of CO2 is formed.
Therefore, the mass of CO2 formed = moles of CuCO3 used × molar mass of CO2
= 0.25 mol × 44 g/mol
= 11 g
So, 11 grams of CO2 is formed.
2) To find the mass of solid remaining after heating, we need to subtract the mass of CuO formed from the initial mass of CuCO3 used.
Molar mass of CuO = 80 g/mol
Moles of CuO formed = moles of CuCO3 used (using the same value of 0.25 mol as calculated above)
Mass of CuO formed = moles of CuO formed × molar mass of CuO
= 0.25 mol × 80 g/mol
= 20 g
Therefore, the mass of solid remaining after heating = initial mass of CuCO3 used - mass of CuO formed
= 31 g - 20 g
= 11 g
So, 11 grams of solid remains after heating.