Carlo is eating a bag of Skittles. In the bag, thre are 5 red, 2 green and 4 purple Skittles. What is the probability that Carlo will pick a red Skittle, eat it and then pick a green Skittle?
prob(picking a red, then a green)
= (5/11)(2/10)
= 1/11
Working in the prob that he will also eat it needs more information.
e.g. How hungry is he?
Will he eat it now, or later, etc
To find the probability that Carlo will pick a red Skittle, eat it, and then pick a green Skittle, we need to consider two events happening consecutively: picking a red Skittle and picking a green Skittle.
First, let's calculate the probability of picking a red Skittle from the bag. There are a total of 5 red Skittles in the bag, and Carlo selects one Skittle at random. Therefore, the probability of picking a red Skittle is:
Probability of picking a red Skittle = Number of red Skittles / Total number of Skittles
Probability of picking a red Skittle = 5 / (5 + 2 + 4)
= 5 / 11
Now let us consider the second event, which is picking a green Skittle. After Carlo has picked and eaten the red Skittle, there are 10 Skittles remaining in the bag (2 green and 4 purple Skittles). Thus, the probability of picking a green Skittle from the remaining options is:
Probability of picking a green Skittle = Number of green Skittles / Total number of remaining Skittles
Probability of picking a green Skittle = 2 / 10
= 1 / 5
To find the probability of both events occurring consecutively, we multiply the probabilities of the two events together:
Probability of picking a red Skittle and then a green Skittle = Probability of picking a red Skittle × Probability of picking a green Skittle
Probability of picking a red Skittle and then a green Skittle = (5 / 11) × (1 / 5)
= 1 / 11
Therefore, the probability that Carlo will pick a red Skittle, eat it, and then pick a green Skittle is 1/11.